Given an array A
of integers, for each integer A[i]
we may choose any x
with -K <= x <= K
, and add x
to A[i]
.
After this process, we have some array B
.
Return the smallest possible difference between the maximum value of B
and the minimum value of B
.
Input: A = [1], K = 0 Output: 0 Explanation: B = [1]
Input: A = [0,10], K = 2 Output: 6 Explanation: B = [2,8]
Input: A = [1,3,6], K = 3 Output: 0 Explanation: B = [3,3,3] or B = [4,4,4]
1 <= A.length <= 10000
0 <= A[i] <= 10000
0 <= K <= 10000
implSolution{pubfnsmallest_range_i(a:Vec<i32>,k:i32) -> i32{letmut min = a.iter().min().unwrap();letmut max = a.iter().max().unwrap();if max - min < 2* k {0}else{ max - min - 2* k }}}